                       Ether andMagnetic field
 Galileo andEinsteinare wrong
 EquivalencePrinciple
 Ether andEquivalencePrinciple
 TECHNOLOGYFusion:The “ZEUS”machine   ETHER AND MAGNETIC FIELD Let us assume (Fig. 1) that there is an electric charge e.g. +q moving at a constant velocity V relative to an observer O’, who is at rest on the surface of the Earth.In addition, r is the distance between the observer O’ and the straight line xx’ along which the electric charge +q moves.Let us assume that at time to the electric charge +q is at a given point Μ (i.e. exactly opposite the observer O’ who is at rest). Consequently, at another time t1, (t1 < to) the electric charge +q was at point Α, where ΑΜ = L.   Fig. 1Based on the above, time t in which the electric charge +q covered the distance ΑΜ = L is:    and the distance ΑΜ = L covered by the electric charge +q is:    As we well know, an electric charge +q moving at a constant velocity V along a straight line xx’ is equivalent to an electric current of intensity i. Thus, in Fig. 1, the electric charge +q which moves over time t and at a constant velocity V from point Α to point Μ is equivalent to a linear electrical conductor of length L. This conductor is flown by an electric current of intensity i.Also, we know that an electrical linear conductor of length L is surrounded by a magnetic field of strength B.Now, the following problem arises:Problem: In Fig. 1, how high is this magnetic field’s strength B measured by the stationary observer O’, when the moving electric charge +q is exactly opposite to him (i.e. at point M)?   To solve this problem, we proceed as follows: SOLUTION According to the Biot-Savart law, we know that for the linear conductor of length L (Fig. 1) flown by an electric current of intensity i, the magnetic field’s strength Β measured by the stationary observer O’ is:    Yet since in Fig. 1:    relation (3) is written as follows:    Also, given that:  and    relation (5) is written as follows:    Therefore, (if t 0 namely L 0) and when the moving electric charge +q reaches point Μ, then given thatR = rrelation (6) is written as follows:    Relation (7) obviously provides the solution to our problem.Note: In relation (7) the magnetic field’s strength Β is measured in Gauss, the electric charge q in Cb, the velocity V in cm/sec, and distance r in cm.In addition, relation (7) results “directly” from the Biot-Savart law, as well, if we consider that at point M there is an elementary electric current of length dL for a time dt,  where dL = V. dt  and BASIC CONCLUSIONS Let us assume (Fig. 1) that there are several observers , being at rest on the surface of the Earth.In this case, when the moving electric charge +q passes directly opposite them, that is, at points , respectively, then (according to the above problem’s solution)  each of the stationary observers ,  will obtain the same result as regards the strength of the magnetic field, which according to relation (7) is:    where ,  are the intensities of the magnetic field measured respectively by the stationary observers .Given, however, that:  a)    andb) Given that the generation of a magnetic field of strength B by a moving electric charge +q (Fig. 1 in our experiment) is a property of Ether in the Earth’s Etherosphere, this signifies that:In Fig. 1, lets consider a railcar S moving at the same velocity V as the electric charge +q. Then: An observer P is on the moving railcar S (and uses a magnetic needle); when the railcar S passes from points ,  (where the stationary observers are found), the observer P shall obtain the same reading for the magnetic field’s strength B as the stationary observers . In other words, the magnetic field’s strength B will be measured at all times by the observer P according to relation (7), namely:    However, since the electric charge +q and railcar S move at the same velocity V, then the electric charge +q is at rest relative to the moving railcar S.Yet (as stated above), the electric charge +q which is at rest relative to the railcar S, generates a magnetic field of strength Β (Relation (10)) relative to the observer  P sitting in the moving railcar S.So, how is this phenomenon explained? We know that according to Classical Physics and the Theory of Relativity “Electric charges which are at rest relative to an inertial frame of reference o.xyz (e.g. railcar S) do not generate any magnetic field for an observer P found in this inertial reference frame  o.xyz, that is, on railcar S”.Therefore, Classical Physics and the Theory of Relativity fail to interpret the phenomenon of magnetic field generation for the observer P sitting in moving railcar S.However, an accurate interpretation of the above phenomenon is provided only by the Electrogravitational Theory, if we accept the existence of Ether and the fundamental “Law of Magnetic field Formation” formulated below: LAW: An electric charge q (either positive or negative) for any observer (either in motion or at rest) creates around the orbit of its movement a magnetic field only:1) When the electric charge q crosses the Ether of a celestial body’s Etherosphere, or2) When the electric charge q crosses the stationary Ether of the universe, which is found outside of the celestial bodies’ Etherospheres.  Note: For information on Ether and the Etherospheres of celestial bodies, See “The Electrogravitational Theory” on www.tsolkas.gr The above-mentioned fundamental law is applied in experiments (4), (5), (9), (15), (16), (17) as detailed on the above website. The error of the Theory of Relativity As it is well known, the Theory of Relativity holds the following: “An observer P found in an inertial frame of reference S cannot prove by any Physics experiment whatsoever (either from the field of Mechanics or electromagnetism) whether this reference frame  S is in motion or at rest relative to another inertial frame of reference S’”.What Einstein asserts is wrong for the following reason:In Fig. 1, the observer P who is inside the inertial frame of reference o.xyz (i.e. the railcar S), by knowing the quantities q and r and by measuring (e.g. with the use of a magnetometer)) the magnetic field’s strength Β, is in a position know on the basis of relation (10) whether the railcar S is in motion or at rest relative to the Earth, S’. Because relation (10) ultimately gives:    Consequently:If the magnetometer used by the observer P on board the railcar S shows Β = 0, then from relation (11) it results that V = 0, and thus, the observer P comes to the conclusion that the railcar S is at rest relative to the Earth S’.If the magnetometer shows B ≠ 0, then from relation (11) ) it results that V≠ 0, and thus, the observer P comes to the conclusion that the railcar S is moving relative to the Earth S’. (See Experiment 15 on www.tsolkas.gr)So, this is where Einstein erred! Therefore, given this error, the postulates of the Special Theory of Relativity are totally wrong. After everything detailed in this chapter, the following conclusion can be drawn: Conclusion Ether exists in Nature.Classical Physics and the Theory of Relativity are founded on an erroneous basis, and for this reason: Classical Physics must be complemented by the existence of Ether in nature, while the Theory of Relativity must be rejected as an utterly false theory of physics.  ©  Copyright 2001 Tsolkas Christos.  Web design by Wirenet Communications